What is the correct expression for average acceleration?

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Multiple Choice

What is the correct expression for average acceleration?

Explanation:
Average acceleration measures how velocity changes per unit time over a time interval. It is defined as a_avg = Δv/Δt, the change in velocity divided by the time over which that change occurs. This makes sense because acceleration is a rate of change: if velocity goes up by 4 m/s over 2 seconds, the average acceleration is 2 m/s^2. For reference, F/m gives acceleration from force and mass, but not the rate of change of velocity over a specific interval; distance divided by time yields speed, not acceleration; and the reciprocal Δt/Δv would invert the concept and not represent the rate of change. As the interval gets smaller, the average acceleration approaches the instantaneous acceleration—the slope of the velocity–time graph.

Average acceleration measures how velocity changes per unit time over a time interval. It is defined as a_avg = Δv/Δt, the change in velocity divided by the time over which that change occurs. This makes sense because acceleration is a rate of change: if velocity goes up by 4 m/s over 2 seconds, the average acceleration is 2 m/s^2. For reference, F/m gives acceleration from force and mass, but not the rate of change of velocity over a specific interval; distance divided by time yields speed, not acceleration; and the reciprocal Δt/Δv would invert the concept and not represent the rate of change. As the interval gets smaller, the average acceleration approaches the instantaneous acceleration—the slope of the velocity–time graph.

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